Se P(x) = 3x ao quadrado +12x -7 então quanto é P (-1)?
Soluções para a tarefa
Respondido por
0
Boa tarde
Basta substituir o -1 no lugar de x, veja:
P(-1)= 3(-1)²+12(-1)-7
P(-1)= 3-12-7
P(-1)= -16
Basta substituir o -1 no lugar de x, veja:
P(-1)= 3(-1)²+12(-1)-7
P(-1)= 3-12-7
P(-1)= -16
Respondido por
0
Dada a função:
Substituindo
teremos:
![\mathsf{P\left(-1\right)=3\left(-1\right)^2+\left[12\cdot \:\left(-1\right)\right]-7}\\\\\mathsf{P\left(-1\right)=\left(3\cdot 1\right)-12-7}\\\\\mathsf{P\left(-1\right)=3-12-7}\\\\\mathsf{P\left(-1\right)=3-19}\\\\\boxed{\mathsf{P\left(-1\right)=-16}}\: \: \checkmark](https://tex.z-dn.net/?f=%5Cmathsf%7BP%5Cleft%28-1%5Cright%29%3D3%5Cleft%28-1%5Cright%29%5E2%2B%5Cleft%5B12%5Ccdot+%5C%3A%5Cleft%28-1%5Cright%29%5Cright%5D-7%7D%5C%5C%5C%5C%5Cmathsf%7BP%5Cleft%28-1%5Cright%29%3D%5Cleft%283%5Ccdot+1%5Cright%29-12-7%7D%5C%5C%5C%5C%5Cmathsf%7BP%5Cleft%28-1%5Cright%29%3D3-12-7%7D%5C%5C%5C%5C%5Cmathsf%7BP%5Cleft%28-1%5Cright%29%3D3-19%7D%5C%5C%5C%5C%5Cboxed%7B%5Cmathsf%7BP%5Cleft%28-1%5Cright%29%3D-16%7D%7D%5C%3A+%5C%3A+%5Ccheckmark "\mathsf{P\left(-1\right)=3\left(-1\right)^2+\left[12\cdot \:\left(-1\right)\right]-7}\\\\\mathsf{P\left(-1\right)=\left(3\cdot 1\right)-12-7}\\\\\mathsf{P\left(-1\right)=3-12-7}\\\\\mathsf{P\left(-1\right)=3-19}\\\\\boxed{\mathsf{P\left(-1\right)=-16}}\: \: \checkmark")
Substituindo
Perguntas interessantes