Question

Se o seno de um ângulo é igual a 0,333, qual é o valor do cosseno e da tangente

desse ângulo?​

Answer 1

$\Large\boxed{\begin{array}{l}\sf sen(x)=0,333....\implies sen(x)=\dfrac{1}{3}\\\sf sen^2(x)=\dfrac{1}{9}^\\\\\sf cos^2(x)=\dfrac{9}{9}-\dfrac{1}{9}=\dfrac{8}{9}\\\\\sf cos(x)=\dfrac{\sqrt{8}}{\sqrt{9}}=\dfrac{2\sqrt{2}}{3}\\\\\sf tg(x)=\dfrac{sen(x)}{cos(x)}=\dfrac{\frac{1}{\backslash\!\!\!3}}{\frac{2\sqrt{2}}{\backslash\!\!\!3}}\\\\\sf tg(x)=\dfrac{1}{2\sqrt{2}}=\dfrac{\sqrt{2}}{2\cdot2}=\dfrac{\sqrt{2}}{4}\end{array}}$