Question

se o log 2=0.301 e log 3=0.477,determine o valor log 6,log 9,log 36.

Answer 1

Olá.
log 6 = log(2*3) = log2 + log3 = 0,301 + 0,477 = 0,778
log 9 = log(3*3) = log3 + log3 = 0,477 *2 = 0,954
log 36 = log(6*6) = log6 + log6 = 0,778 * 2 = 1,556

Bju ^^)

Answer 2

$Ola'! \\ \\ log6=log(2.3)=log2+log3=0.301+0.477=\boxed{ 0,778} \\ \\ log9=log3\²=2log3=2(0.477)=\boxed{0,954} \\ \\ log36=log(2\².3\²)=2log(2.3)=2[log2+log3]=2[0.301+0.477] \\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=2[0.778]=\boxed{1,556} \\ \\ \\ Espero~ter~ajudado!$