Question

Se m=(3^5.4^3)²(3².4^-6)-¹ então

A)m= (3^3 . 4^2)^2
B) m= (3^2 . 4^3)^4
C) m= (3^7 . 4^-3)^-2
D) m= (3^10 . 4^-18)^-2



com cálculos pfvr!!!

Answer 1

Bom dia Serana

m = (3^5 * 4^3)² * (3².4^-6)^-¹

m = (3^5 * 4^3)² / (3² * 4^-6)

m = 3^(10 - 2) * 4^(6 + 6) 

m = 3^8 * 4^12 

m = (3^2 * 4^3)^4 (B)