Question

Se log2 = 0, 301 e log3 = 0,477, determine:

A.log8
B.log48
C.log200
D.log1,5

Answer 1

Resposta:

log 2 =0,301     log3 = 0,477

a) log 8 = log 2³ = 3log 2 = 3*0,301 = 0,903 ***************

b) log 48      log 2^4 * 3 =  4log 2 +log 3 = 4*0,301 + 0,477 = 1,681 **********

c) log 200 = log 100 *2 = log 100 + log 2 = 2 + 0,301 = 2,301 ****************

d) log 1,5  = log 15 / 10 = log 15 - log 10 =

log 3 * 5 - log 10 = log 3 + log 5 -log 10  >>>

log 3 + log 10/2  - log 10 = log3+log10 -log2 -log 10 = log 3 - log 2 >>>

log 3 - log 2 = 0,477 - 0,301 = 0,176  >>

então log 1,5 = 0,176 *******

Explicação passo-a-passo: