Question

se log2=0,30 e log3=0,48 calcule log5

Answer 1

Olá Patricia,

use as propriedades..

quociente.................$\log\left( \dfrac{a}{b}\right)\Rightarrow \log(a)-\log(b)$

decorrente da definição (D2).....................$\log_b(b)=1$

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$\log(5)= \log\left(\dfrac{10}{2}\right)\\\\ \log(5)=\log(10)-\log(2)\\ \log(5)=\log_{10}(10)-\log(2)\\\\ \log(2)=0,30~~e~~\log_{10}(10)=1~~lembra??\\\\ \log(5)=1-0,30\\\\ \Large\boxed{\log(5)=0,7}$