Question

Se log p = 10, log q = 4 e log k = 3, então o dobro de log p ( base q) - log (k/p) vale:

(a) 19/2
(b) 9
(c) 19
(d) 20
(e) 25​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log\:p = 10}$

$\mathsf{log\:q = 4}$

$\mathsf{log\:k = 3}$

$\mathsf{2\left(\:log_q\:p - log\:\dfrac{k}{p}\right)}$

$\mathsf{2\left(\:\dfrac{log\:p}{log\:q} - (log\:k - log\:p)\right)}$

$\mathsf{2\left(\:\dfrac{log\:p}{log\:q} - log\:k + log\:p\right)}$

$\mathsf{2\left(\:\dfrac{10}{4} - 3 + 10\right)}$

$\mathsf{2\left(\:\dfrac{10 - 12 + 40}{4}\right)}$

$\mathsf{2\left(\:\dfrac{38}{4}\right)}$

$\mathsf{2\left(\:\dfrac{19}{2}\right)}$

$\boxed{\boxed{\mathsf{2\left(\:log_q\:p - log\:\dfrac{k}{p}\right) = 19}}}\leftarrow\textsf{letra C}$