Question

Se log E = 1 + log a + 2 log b – log c, determine E

Answer 1

Boa noite

log(E) = 1 + log(a) + 2log(b) - log(c)

log(E) = log(10) + log(a) + log(b²) - log(c)

log(E) = log(10ab²/c)

E = 10ab²/c

Answer 2

$Ola' \\ \\ logE=1+log~a+2log~b-log~c \\ \\ logE=log10+log~a+2log~b-log~c \\ \\\not logE=\not log[ \frac{10.a. b^{2} }{c}] \\ \\\boxed{ E= \frac{10ab\²}{c}} \\ \\ \\ Espero~ter~ajudado!$