Question

Se log a^m =P e log a^m = Q com P+Q= log a ^x e P-Q = log a^y, obtendo o valor de m^2.

Answer 1

mloga=p  >>>>> mloga=Q
P + Q = xloga
P - Q = yloga
2P = xloga + yloga
2P = loga(x+y)
P= loga(x+y)/2 > loga(x+y)/2 + Q = xloga > Q = xloga - logax/2 - yloga/2
                                                                      Q= xloga - yloga/2 > Q = loga(x-y)/2 
mloga=P
mloga= loga(x+y)/2
m=(x+y)/2 >>>>>>>>>>>>>>>>>>>>>>> Q=mloga
                                                                loga(x-y)/2= m loga
                                                                     m= x-y/2
m=m
x+y/2=x-y/2
x+y = x-y
x - x = -y -y
0= -2y
y=0 >>>>m=x/2
                m= x´2/4