Question

se log (a-b) na base 5 = x e a + b = 25, entao o valor de log (a^2 - b^2) em função de x é:

Answer 1

$\log_{5}(a-b)=x$

$a+b=25$

$\log_{5}(a^{2} -b^{2} )$

$\log_{5}(a+b).(a-b)$

$\log_{5}(a+b)+\log_{5}(a-b)$

$\log_{5}25+x$

$\log_{5}5^{2} +x$

$2.\log_{5}5 +x$

$2.1 +x$

$x+2$

Portanto: $\log_{5}(a^{2} -b^{2} )=x+2$

Answer 2

Resposta:

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