Se log 2= a e log 3= b, calcule em função de a e b os seguintes logaritmos:
a) log 6
b) log 4
c) log 12
d) log
e) log0, 5
f) log 20
g) log 5
h) log 15
*Põe as respostas com o calculo quero entender as respostas! ME AJUDEM!!
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Oi . Segue. Comenta depois :)
a) log 6
log 2*3 -> log 2 + log 3 -> a+b
b) log 4
log 2² -> 2log 2 -> 2a
c) log 12
log 2².3 -> 2.log 2 + log 3 -> 2a+b
d) log ?????
e) log0, 5
log 5/10 -> log 5 - log10 -> log 10/2 - 1 -> log 10 - log2 - 1 -> 1-a-1 -> -a
f) log 20
log 2².5 -> 2log 2 + log 5 -> 2a + log 10/2 -> 2a+ log10 - log2 ->
-> 2a+1-a -> a+1
g) log 5
log 10/2 -> log 10 - log2 -> 1 -a
h) log 15
Log 3.5 ->. log 3 + log 5 -> b + log 10/2 -> b + log10 - log 2 -> b+1-a
a) log 6
log 2*3 -> log 2 + log 3 -> a+b
b) log 4
log 2² -> 2log 2 -> 2a
c) log 12
log 2².3 -> 2.log 2 + log 3 -> 2a+b
d) log ?????
e) log0, 5
log 5/10 -> log 5 - log10 -> log 10/2 - 1 -> log 10 - log2 - 1 -> 1-a-1 -> -a
f) log 20
log 2².5 -> 2log 2 + log 5 -> 2a + log 10/2 -> 2a+ log10 - log2 ->
-> 2a+1-a -> a+1
g) log 5
log 10/2 -> log 10 - log2 -> 1 -a
h) log 15
Log 3.5 ->. log 3 + log 5 -> b + log 10/2 -> b + log10 - log 2 -> b+1-a
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