se k+ 1/i = 1 - 3i então k vale
a)3
b)-3
c)5
d)-5
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Solução!
![\dfrac{K+1}{i}=1-3i \\\\\\
K+1=i(1-3i)\\\\\\
K+1=i-3i^{2} \\\\\\\
Lembrando\\\\\
i^{0}=1\\\\
i^{2}=-1\\\\\\
K+1=1-3(-1) \\\\\\\
K+1=1+3\\\\\
K=1-1+3\\\\
K=0+3\\\\
K=3\\\\\\
Resposta:Alternativa~~A](https://tex.z-dn.net/?f=+%5Cdfrac%7BK%2B1%7D%7Bi%7D%3D1-3i+%5C%5C%5C%5C%5C%5C%0AK%2B1%3Di%281-3i%29%5C%5C%5C%5C%5C%5C%0AK%2B1%3Di-3i%5E%7B2%7D+%5C%5C%5C%5C%5C%5C%5C%0ALembrando%5C%5C%5C%5C%5C%0Ai%5E%7B0%7D%3D1%5C%5C%5C%5C%0Ai%5E%7B2%7D%3D-1%5C%5C%5C%5C%5C%5C%0A+K%2B1%3D1-3%28-1%29+%5C%5C%5C%5C%5C%5C%5C%0AK%2B1%3D1%2B3%5C%5C%5C%5C%5C%0AK%3D1-1%2B3%5C%5C%5C%5C%0AK%3D0%2B3%5C%5C%5C%5C%0AK%3D3%5C%5C%5C%5C%5C%5C%0AResposta%3AAlternativa%7E%7EA "\dfrac{K+1}{i}=1-3i \\\\\\
K+1=i(1-3i)\\\\\\
K+1=i-3i^{2} \\\\\\\
Lembrando\\\\\
i^{0}=1\\\\
i^{2}=-1\\\\\\
K+1=1-3(-1) \\\\\\\
K+1=1+3\\\\\
K=1-1+3\\\\
K=0+3\\\\
K=3\\\\\\
Resposta:Alternativa~~A")
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Bons estudos!
Solução!
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Bons estudos!
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