Question

Se f(x)=x+1 e F(x;y)=y²+x, então F(2;f(3)) igual a

Answer 1

f(x) = x+1
f(x,y) = y²+x
f(2,f(3)) = [f(3)]²+2
f(3) = 3+1
f(3) = 4
[f(3)²]+2 =
4²+2 = 
16+2 = 18