Question

Se f(x) = 161+1/x, calcule o valor de : f(-1) + f(-2) + f(-4)

Answer 1

A resposta vai em anexo ok.

Answer 2

Olá !! Paulinha!!

 

Vamos calcular cada um separadamente

 

 $f(x)=161+\frac{1}{x}$

 

 $f(-1)=161+\frac{1}{-1}$

 

 $f(-1)=161-1$ >>>>>>>>>>>>>>>>>>>>$f(-1)=160$

 

 

$f(x)=161+\frac{1}{x}$

 

$f(-2)=161+\frac{1}{-2}$

 

$f(-2)=161-\frac{1}{2}$

 

$f(-2)=\frac{161.2}{1.2}-\frac{1}{2}$

 

$f(-2)=\frac{322}{2}-\frac{1}{2}$ >>>>>>>>>>>$f(-2)=\frac{321}{2}$

 

 

$f(x)=161+\frac{1}{x}$

 

$f(-4)=161+\frac{1}{-4}$

 

$f(-4)=161-\frac{1}{4}$

 

$f(-4)=\frac{161.4}{1.4}-\frac{1}{4}$

 

$f(-4)=\frac{644}{4}-\frac{1}{4}$ >>>>>>>>>>>>$f(-4)=\frac{643}{4}$

 

FINALMENTE .....

 

f(-1) + f(-2) + f(-4)

 

$160+\frac{321}{2}+\frac{643}{4}$    MMC = 4

 

$\frac{160.4}{1.4}+\frac{321.2}{2.2}+\frac{643}{4}$

 

$\frac{640+642+643}{4}$

 

$\Large{\boxed{\frac{1925}{4}}}$

 

veja se entendeu