Se determinante A= ![\left[\begin{array}{ccc}a&b&\\c&d&\\\end{array}\right] =10,calcule \\ <br />
a) det A= \left[\begin{array}{ccc}b&a&\\d&c&\\\end{array}\right] \\ b) det B= \left[\begin{array}{ccc}4a&4b&\\c&d&\\\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26amp%3Bb%26amp%3B%5C%5Cc%26amp%3Bd%26amp%3B%5C%5C%5Cend%7Barray%7D%5Cright%5D+%3D10%2Ccalcule+%5C%5C+%3Cbr+%2F%3E%0Aa%29+det+A%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db%26amp%3Ba%26amp%3B%5C%5Cd%26amp%3Bc%26amp%3B%5C%5C%5Cend%7Barray%7D%5Cright%5D++%5C%5C+b%29+det+B%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4a%26amp%3B4b%26amp%3B%5C%5Cc%26amp%3Bd%26amp%3B%5C%5C%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}a&b&\\c&d&\\\end{array}\right] =10,calcule \\ <br />
a) det A= \left[\begin{array}{ccc}b&a&\\d&c&\\\end{array}\right] \\ b) det B= \left[\begin{array}{ccc}4a&4b&\\c&d&\\\end{array}\right]")
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bom calculando o determinante dado fica:
a.d - bc =10
a)
Calculando o determinante :
-ad+bc=x
-x=ad-bc
Se ad-bc =10 , Então substituindo em :
-x=ad-bc
-x=10 (-10)
x=-10
Logo detA= -10
b)
Calculando o determinante :
4ad-4bc=x
4(ad-bc)=x
Se ad-bc =10 , Então substuindo em :
4(ad-bc)=x
4(10)=x
x=40
Logo detB= 40
a.d - bc =10
a)
Calculando o determinante :
-ad+bc=x
-x=ad-bc
Se ad-bc =10 , Então substituindo em :
-x=ad-bc
-x=10 (-10)
x=-10
Logo detA= -10
b)
Calculando o determinante :
4ad-4bc=x
4(ad-bc)=x
Se ad-bc =10 , Então substuindo em :
4(ad-bc)=x
4(10)=x
x=40
Logo detB= 40
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