Question

Se ㏒ de 2 elevado a n na base n = n/4, n>0 e n diferente de 1, então n =?

Answer 1

Resposta:

$log_{n}( {2}^{n} ) = \frac{n}{4} \\ {n}^{ \frac{n}{4} } = {2}^{n} \\ {n}^{ \frac{1}{4} .n} = {2}^{n} \\ { ({n}^{ \frac{1}{4} } )}^{n} = {2}^{n} \\ {n}^{ \frac{1}{4} } = 2 \\ n = {2}^{4} \\ n = 16$

Letra d)