Question

Se alguém puder me ajudar, exercício 4.

Answer 1

Resolvendo os logs
1°

$\log_{10}~~10^{-3}=x~~~\to~10^x=10^{-3}~~~\boxed{x=-3}$

2°

$\log_2~~4 \sqrt{32}=y\\ \\2^y=4 \sqrt{32} \\2^y=16 \sqrt{2} \\2^y=2^4*2^{ \frac{1}{2} }\\ \\2^y=2^{ \frac{9}{2} }\\ \\\boxed{y= \frac{9}{2} }$

3°
$\log_2~~ \frac{1}{8} =z\\2^z= \frac{1}{8} \\2^z=2^{-3}\\ \\\boxed{z=-3}$

Fazendo as operações 

$x+y-z\\ \\\boxed{-3+ \frac{9}{2} -3=-\frac{3}{2} ~~\to~-1,5}$

Alternativa B