Question

Se a nova parte do numero real 81^0,25.(3^2)^20.3^5^2/(1/243)^24 = 3^x, calcule o valor de x

Answer 1

Resposta:

Leia abaixo

Explicação passo-a-passo:

$\dfrac{81^{0,25}.((3)^2)^{20}.((3^5))^2}{(\dfrac{1}{243})^{24}} = 3^x$

$\dfrac{3.3^{40}.3^{10}}{3^{-120}} = 3^x$

$\dfrac{3^{51}}{3^{-120}} = 3^x$

$3^{171} = 3}^x$

$\boxed{\boxed{x = 171}}$