Question

Se A= log1/5 16 * log16 1/5 e B= 1/log25 5, determine:

a) A+B
b) A:B

Answer 1

$A=\log_ \frac{1}{5}16.\log_{16} \frac{1}{5}$
$A=\log_ \frac{1}{5}16. \frac{1}{\log_ \frac{1}{5}16 }$
$A=1$

$B= \frac{1}{\log_{25}5}$
$B= \frac{1}{ \frac{1}{\log_525} }$
$B= \frac{1}{ \frac{1}{2} }$
$B=1.2$
$B=2$

$a)A+B=1+2=3$
$b) \frac{A}{B}= \frac{1}{2}$