Question

se a= log 2 1 024+ log 1 sobre 5 625 determine o valor de a

Answer 1

log2(1024) = x
2^x = 1024
2^x = 2^10
x = 10

log1/5(625) = y
(1/5)^y = 625
(5^-1)^y = 5^4
5^-y = 5^4
-y = 4
y = -4

A = log2(1024) + log1/5(625)
A = x + y
A = 10 + (-4)
A = 6

Answer 2

a= log 2 1 024+ log 1 sobre 5 625 
log 1024 = x ==> 2^x = 1024 ==> 2^x = 2^10 ==> x= 10
     2
 

log 625 = y ==> 5^y = 625 ==> 5^y = 5^4 ==> y= 4
     5
  

A = x + y ==> A = 10 + 4 ==> A = 14