Question

Se a= -5/3,b = 11/6 e c =3/2.QUANTO É a) a+b b)-a-c c)b-c d)a+b+c ????????AJUDAA

Answer 1

Resposta:

Explicação passo-a-passo:

Se a= -5/3,b = 11/6 e c =3/2.

a) a+b

= -5/3 + 11/6

mmc (3,6) = 6

= [2.(-5) + 11]/6

= (-10+11)/6

= 1/6

b)-a-c

= -(-5/3) - 3/2

= 5/3 - 3/2

= (2.5 - 3.3)/6

= (10-9)/6

= 1/6

c)b-c

= 11/6 - 3/2

Mmc (6,2)= 6

= [11 - 3.3)]/6

= (11-9)/6

= 2/6 (:2)/(:2)

= 1/3

d)a+b+c

= -5/3 + 11/6 + 3/2

Mmc (3,6,2) = 6

= [2.(-5) + 11 + 3.3]/6

= [-10+11 + 9]/6

= (1+9)/6

= 10/6 (:2)/(:2)

= 5/3