Question

Se a=(3 1/3) elevado à -1, qual o valor de b considerando que a+b=1

Answer 1

Temos um sistema:

$\left \{ {{(3\frac{1}{3})^{-1} =\ a} \atop {a+b=1}} \right.\\\\(3 \frac{1}{3})^{-1} = \frac{1}{(\frac{10}{3})}=1:\frac{10}{3} = 1* \frac{3}{10} = \frac{10}{3}$

Assim $a=\frac{10}{3}$

Como a+b=1, e a=10/3, então...

$\frac{10}{3}+b=1\\\\ \frac{10}{3}+ \frac{b}{1}= \frac{1}{1} \\\\ \frac{10}{3} + \frac{3b}{3}= \frac{3}{3} \\\\10+3b=3\\\\ 3b=3-10\\\\3b=-7\\\\b= \frac{-7}{3}$

$a= \frac{10}{3}\ e\ b= \frac{-7}{3}$