Question

se (4, x, 21,...) e (12, 18, y,...) forem proporcionais, entao o valor de x+y é:

Answer 1

$\geqslant \: resolucao \\ \\ \\ 4 \: \: \: x \: \: 21 \\ 12 \: \: 18 \: \: y \\ \\ \\ \frac{4}{12} = \frac{x}{18} \\ \\ 12x = 4 \times 18 \\ 12x = 72 \\ x = \frac{72}{12} \\ x = 6 \\ \\ = = = = = = = = = = = = = = = = = \\ \\ \\ \frac{6}{18} = \frac{21}{y} \\ \\ 6y = 18 \times 21 \\ 6y = 378 \\ y = \frac{378}{6} \\ y = 63 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$

= x + y

= 6 + 63

= 69

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