Question

se 3 elevado a x-1,+3 elevado a x+3 = 82/9 entao 2 elevado a x é igual a A)1/4 B) 1/2 C)2 D)4
​

Answer 1

${3}^{x - 1} + {3}^{x + 3} = \frac{82}{9} \\ \\ {3}^{x - 1} + {3}^{x + 3} = \frac{ {3}^{4} + {3}^{0} }{ {3}^{2} } \\ \\ {3}^{x - 1} + {3}^{x + 3} = {3}^{4} + {3}^{0} \div {3}^{2} \\ \\ x - 1 + x + 3 = 4 + 0 \div 2 \\ 2x + 3 - 1 = 4 + 0 \\ 2x = 4 + 0 - 3 + 1 \\ 2x = 2 \\ x = 2 \div 2 \\ x = 1$