Question

Se 2^x=6, então log 3 na base 2 é?

Answer 1

$2^x=6\\\\aplicando\;log\;de\;^base \;2:\\\\log_{_2}2^x=log_{_2}6\\\\x=log_{_2}6\\\\x=log_{_2}(3\;.\;2)\\\\Utilizando\;a\;propriedade\;:\;log(a.b)=log\,a+log\,b:\\\\x = log_{_2}3+log_{_2}2\\\\x=log_{_2}3+1\\\\log_{_2}3=x-1$