Question

Se 2^x=4^y+1 e 27^y=3x-9, então y-x vale:

Answer 1

2^x = 4^y+1 => 2^x = (2^2)^y+
x = 2y+2
y = (x-2)/2

27^y = 3(2y+2)
27^y = 6y +6