Question

( saresp) quais sao as raizes da equaçao x²+10x+16=0?
a- 2 e 8
b -2 e -8
c 5 e -5
d -16 e -4

Answer 1

$x^{2} +10x+16=0 \\ \\a=1;b=10;c=16 \\ \\ \Delta= b^{2} -4ac \\ \Delta= 10^{2} -4*1*16 \\ \Delta=100-64 \\ \Delta=36 \\ \\ \\ x= \frac{-b+- \sqrt{\Delta} }{2a} \\ \\ x= \frac{-10+- \sqrt{36} }{2*1} \\ \\ x= \frac{-10+-6}{2}$




$x'= \frac{-10+6}{2} \\ x'= \frac{-4}{2} \\ x'=-2 \\ \\ \\ x''= \frac{-10-6}{2} \\ x''= \frac{-16}{2} \\ x''=-8 \\ \\ \\ \\ S=(-2,-8)$



Resposta Correta: Letra B) -2 e -8.

Answer 2

Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

$\sf x^2+10x+16=0$

$\sf x^2+10x+16-16=-16$

$\sf x^2+10x=-16$

$\sf x^2+10x+5^2=-16+5 ^2$

$\sf x^2+10x+25=-16+25$

$\sf x^2+10x+25=9$

$\sf (x+5)^2=9$

$\sf \sqrt{\sf (x+5)^2 } =\sqrt{9}$

$\sf x+5=3\\x+5=-3$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{x=-2}}}}\ \checkmark\\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \green{x=-8} }}}\ \checkmark$←↑←↑ RESPOSTA.

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