Question

SAO DADAS AS IGUALDADES A)X+1/5=2X+6/15 B)3Y-10/5Y+2=10/5

Answer 1

A)X+1/5=2X+6/15
X-2X= - $\frac{1}{5} + \frac{6}{15}$
-x=$\frac{6-3}{15}$                          MMC
-x=$\frac{3}{15}$
-x= 1/5 (-1)
X= - 1/5

B)3Y-10/5Y+2=10/5
    3Y- 10/5Y= 2 - 2
    3Y- 10/5Y= 0
     $\frac{15 Y^{2} +10}{5Y}$= 0
    $15Y^{2} -10=0     Y= \frac{\sqrt{10} }{15}$$15 Y^{2} - 10 = 0. 5Y$