Question

Sabendoque logca = 6,42 ; logcb = 4,21 ; logcd = 2,31 determine logc [ (a2.b5) / (b2.d6) ]?ALTERNATIVAS :A.21,32B.14,82C.11,61D.39,33E.25,61

Answer 1

$log_{c}a =6,42; log _{c} b=4,21 ;log_{c} d=2,31 \\ \\ log _{c} \frac{a^2.b^5}{b^2d^6} =log _{c}a^2.b^5-log _{c} b^2.d^6=2log _{c}a+5log _{c}b-(2log _{c} b)+6log _{c}d) \\ \\ 2log _{c}a+5log _{c}b-2log _{c}b-6log _{c} d \\ \\ =2*6,42+5*4,21-2*4,21-6*2,31 =\\\\</span>$ \\ \\ 12,84+21,05-8,42-13,86=33,89-22,28=11,61 \\ \\ LetraC[/tex]