Question

sabendo-se que y= raiz a/b.c,entao log y é igual a

Answer 1

 log y , sendo y = $\frac{ \sqrt{a} }{b.c}$
 
 
 log.$( \frac{ \sqrt{a} }{b.c})$

$log= ( log.a^{ \frac{1}{2} } - log.({b.c)})   *log.a^{ \frac{1}{2}} =\ \textgreater \ a^{ \frac{1}{2} } =\ \textgreater \ \frac{1}{2}.     log.a     *log.({b.c) = (log.b+logc)$


Unindo fica:
       log($\frac{1}{2}. log.a - (log.b+logc)$)