Question

Sabendo-se que x/12, y/28 , z/20 são iguais e x+2y+5z=42 Calcule os valores de x ,y ,e z

Answer 1

Olá

x/12 =  y/28 = z/20

x + 2y + 5z =42

x /12+ 2(y/28)  = 5 (z/20)  =

x /12  =  2y/28 = 5z/20  = ( x + 2y + 5z)/ ( 12 + 28 + 20) = 42/60 =7/10

x/12 = 7/10

10x = 7 * 12

10x = 84

x = 84/10 = 8,4 ***

2y/28 =7/10

20y = 28 * 7

20y = 196

y = 196/20 =9,8 ****

5z/20 =   7/10

50z = 20 * 7

50z = 140

z = 140/50 =2,8 ****

8,4 + 2 (9,8) + 5 (2,8 )  = 42

8,4 + 19,6 + 14 = 42