Question

sabendo -se que log 2= a e log 3 = b , pode-se dizer que log 24 é?​

Answer 1

loga(x) = 2

logb(x) = 3

logc(x) =5

calcule o valor de logabc(x)

logabc(x) = 1/logx(abc)

= 1/(logx(a) + logx(b) + logx(c))

= 1/(1/loga(x) + 1/logb(x) + 1/logc(x))

=  1/(1/2) + 1/3 + 1/5)

= 1/(15/30 + 10/30 + 6/30)

= 1/(31/30) = 30/31