Question

sabendo que (x+y)²=(x+y)×(x+y), cacule aplicando a propriedade distributiva:

a)   (x+y)²      c)   (x-y)²

b)   (-x-y)²       d)  (-x-y)²

Answer 1

$a)\ (x+y)^2=(x+y)(x+y) = x^2+xy+xy+y^2 = x^2+2xy+y^2\\\\b)\ (-x-y)^2=(-x-y)(-x-y) = x^2+xy+xy+y^2 = x^2+2xy+y^2\\\\c)\ (x-y)^2 = (x-y)(x-y) = x^2-xy-xy+y^2 = x^2-2xy+y^2\\\\d)\ (-x-y)^2=(-x-y)(-x-y) = x^2+xy+xy+y^2 = x^2+2xy+y^2$

Espero ter ajudado. :))