Question

sabendo que tg (x +y) = 33 e tgx=3 , calcule tg y

Answer 1

Oi Lukas.

$tg(x+y)=33\\ \\ tgx=3\\ \\ \\ tg(x+y)=\frac { tgx+tgy }{ 1-tgx*tgy } \\ \\ 33=\frac { 3+tgy }{ 1-3*tgy } \\ \\ (1-3*tgy)33=3+tgy\\ 33-99tgy=3+tgy\\ -99tgy-tgy=3-33\\ -100tgy=-30\quad (-1)\\ 100tgy=30\\ tgy=\frac { 30 }{ 100 } \leftrightarrow \frac { 3 }{ 10 }$