Question

Sabendo que tg(x) = ½ e tg(x) = ⅔, determine tg(x+y).

Answer 1

Resposta:

vou somar aqui ja volto ta bom

Answer 2

$\displaystyle \underline{\text{Arco soma da tangente}}: \\\\ \text{Tg(x+y)} = \frac{\text{Tg(x) + Tg(y) }}{1-\text{Tg(x).Tg(y)}} \\\\\\\text{temos}: \\\\ \text{Tg(x)}=\frac{1}{2} \ ;\ \text{Tg(y)}=\frac{2}{3} \\\\\\ \text{Tg(x+y) } = \frac{\displaystyle\frac{1}{2}+\frac{2}{3} }{\displaystyle 1-.\frac{1}{2}\frac{2}{3}} \\\\\\ \text{Tg(x+y)}=\frac{\displaystyle \frac{3.1+2.2}{6}}{\displaystyle \frac{6-2}{6}} \\\\\\\ \huge\boxed{\text{Tg(x+y)}=\frac{7}{4}\ }\checkmark$