Question

sabendo que $log 6_{5}$= 0,898 e $log _6{2}$= 0,386 calcule: 
 $log 6_{20}$

Answer 1

I) 20 = 4 . 5 = 2^{2} . 5

II) log_{6}20 = log_{6}2^{2}.5 = log_{6}2^{2} +log_{6}5

= 2log_{6}2 + log_{6}5 = 2 . 0,386 + 0,898 = 1,67