Question

Sabendo que sen x = 3/5

e que x pertence ao 1º quadrante ,determine :

1)sec x = ?


2) cotg x = ?


3)cossec x = ?​

Answer 1

a:hipotenusa

b:cateto oposto

c:cateto adjacente

sen(x)=b/a=3/5  ==> b=3a/5

a²=b²+c²

25a²/25=9a²/25+c²

16a²/25=c²   ==>c= 4a/5

cos(x)=c/a=(4a/5)/(a) =4/5

1) sec(x)=1/cos(x) =1/(4/5) =5/4

2)cotg(x)=cos(x)/sen(x) = (5/4)/(3/5)=25/12

3)cossec(x)=1/sen(x)=1/(3/5)=5/3