Question

SABENDO QUE SEC X =5/2 E 3PI/2<X<2PI,OBTENHA AS DEMAIS RAZÕES TRIGONOMÉTRICA DE X . 

Answer 1

1/cos x = 5/2

5 cos x = 2

cos x = 2/5

 

sen²x + cos²x = 1

sen²x + (2/5)² = 1

sen²x = 1 - 4/25

sen²x = 21/25

sen x = -\/21/5

 

tg x = sen x / cos x

tg x = \/21/5 / 2/5

tg x = -\/21/2

 

cotg x = cos x / sen x

cotg x = 2/5 / \/21/5

cotg x = 2 / \/21 --> cotg x = -2\/21 / 21

 

cosec x = 1/sen x

cosec x = 1 / \/21/5

cosec x = 5/\/21 --> sec x = 5\/21 / 21