Question

Sabendo que o sen 30° =1/2
e
e o cos 30° = √3/2
determine a tg 30°.​

Answer 1

$\boxed{\boxed{\boxed{\mathsf{tg(x)=\dfrac{sen(x)}{cos(x)}}}}}$

$\mathsf{tg(30^{\circ})=\dfrac{sen(30^{\circ})}{cos(30^{\circ})}}\\\mathsf{tg(30^{\circ})=\dfrac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}}$

$\mathsf{tg(30^{\circ})=\dfrac{1}{2}.\dfrac{2}{\sqrt{3}}}$

$\mathsf{tg(30^{\circ})=\dfrac{1}{\sqrt{3}}}$

$\boxed{\boxed{\boxed{\mathsf{tg(30^{\circ})=\dfrac{\sqrt{3}}{3}}}}}$