Question

sabendo que logbx=-2 e logby =3,caclcule logb
(y2 x)=

Answer 1

Explicação passo-a-passo:

$log_{b}( {y}^{2} x) = log_{b}( {y}^{2} ) + log_{b}(x)$

$= 2log_{b}(y) + log_{b}(x)$

$= 2(3) + ( - 2)$

$= 6 - 2$

$= 4$