Question

sabendo que log6 5 = 0,898 e log de6 2 = 0,386 calcular o log6 10

Answer 1

$log_{6} 10=$$log_{6} (2 . 5) =$

$log_{6} 10=$$log_{6} 2+ log_{6} 5=$

$log_{6} 10=$0,386 + 0,898 

$log_{6}10=1,284$