Question

Sabendo que Log2 = x, calcule Log de 20 na base 2

Answer 1

$Ola'! \\ \\ log_220=?~~~--\ \textgreater \ sabendo~que:\begin{cases}log2=x\end{cases} \\ \\ Ent\~ao: \\ \\ log_220=log_2(10.2)~~~por~propriedade. \\ \\ ~~~~~~~~~~=log_210+\underbrace{log_22}_{1} \\ \\ ~~~~~~~~~~=log_210+1~~~~--\ \textgreater \ Outra~propriedade~de~log. \\ \\ ~~~~~~~~~~= \frac{\overbrace{log10}^{1}}{\underbrace{log2}_{x}} +1 \\ \\ ~~~~~~~~~~= \frac{1}{x}+1 \\ \\\boxed{\boxed{ log_220= \frac{1}{x}+1}} \\ .$

Answer 2

Resposta:

1+x/x

Explicação passo-a-passo:

Na foto ✌️