Question

Sabendo que log2=0,301, log3=0,477 e log5=0,699, resolva a equação exponencial

A) 3 x-1=5

Answer 1

$3^{x-1}-=5\\ log_{10}^{3^{x-1}}=log_{10}^{5}\\ (x-1)log_{10}^{3}=log_{10}^{5}\\ (x-1)0,477=0,699 x-1 =\frac{0,699}{0,477} =1,4654 =\ \textgreater \ x=2,4654$