Question

sabendo que log2=0,3;log3=0,4;log5=0,7
calcule:
$log_{3}(45)$
​

Answer 1

Resposta:

$\log_3(45)\\ \\ mudar~~a~~~base\\ \\ {log45\over log3}\\ \\ {log3^2.5\over log3}=\\ \\ {2log3+log5\over log3}=\\ \\ {2(0,4)+0,7\over0,4}=\\ \\ {0,8+0,7\over0,4}={1,5\over0,4}=3,75$