Question

sabendo que log2=0,3 e log3=0,5,calcule log 6 de base4

Answer 1

Bom dia

$log_{4}6= \frac{log6}{log4} = \frac{log2*3}{log 2^{2} } = \frac{log2+log3}{2*log2} = \frac{0,3+0,5}{2*0,3}= \frac{0,8}{0,6} = \frac{8}{6} = \frac{4}{3}$