Question

sabendo que log a=2 é logb=-1, calcule o valor de:

f) log raizb a

Answer 1

$log_{ \sqrt{b} }(a) \\ \\ \frac{ log(a) }{ log( \sqrt{b} ) } \\ \\ \frac{ log(a) }{ log( {b}^{ \frac{1}{2} } ) } \\ \\ \frac{ log(a) }{ \frac{1}{2} \times log(b) } \\ \\ \frac{2}{ \frac{1}{2} \times ( - 1)} \\ \\ \frac{2}{ - \frac{1}{2} } \\ \\ 2 \times \frac{ - 2}{1} = - 4$