Question

sabendo que log 2=x, log 3=y e log 5=z. calcule: log 7,5

Answer 1

$log(7.5) \\ \\ log( \frac{15}{2} ) \\ \\ log(15) - log(2) \\ \\ log(3 \times 5) - log(2) \\ \\ ( log(3) + log(5) ) - log(2) \\ \\ (y + z) - x \\ \\ -x + y + z$


log 7,5 = -x+y+z