Question

Sabendo que log 2 = a e log 3 = b , calcule, em
função de a e b, o valor de log ∛12.

Answer 1

Resposta:

log ∛12

=log 12^(1/3)

=(1/3)* log 12

=(1/3)* log(2²*3)

=(1/3)* (log 2²+ log 3)

=(1/3)* (2*log 2+log 3)

=(1/3) * (2*a +b)

log ∛12  =  2a/3 +b/3