Question

sabendo que log 2= 0,301 e log 3= 0,477 então o valor do log 36 será ?
​

Answer 1

• Primeira forma de resolver:

$log(36) =$

$log(6 \times 6) =$

$log(6) + log(6) =$

$2 \times log(6) =$

$2 \times log(2 \times 3) =$

$2 \times log(2) + 2 \times log(3) =$

$2 \times 0.301 + 2 \times 0.477 = 1.556$

• Segunda forma de resolver:

$log( {6}^{2} ) =$

$2 log(6) =$

$2 \times log(3 \times 2) =$

$2 \times ( log(2) + log(3) ) =$

$2 \times (0.301 + 0.477) = 1.556$