Question

Sabendo que log 2 = 0 , 3 e log 3 = 0 , 48 , calcule: a) log 6 b) log 1 , 5 c) log 5

Answer 1

Entre as propriedades dos logaritmos temos:

$log(a \times b) = log(a) + log(b) \\ log(a ) - log(b) = log( \frac{a}{b} )$

$log(6) = log(2 \times 3) = log(2) + log(3) \\ log(6 ) = 0.3 + 0.48 \\ log(6) = 0.78$
$log(1) = 0$

$log(5) = log( \frac{10}{2} ) \\ \\ log(5) = log(10) - log(2) \\ log(5) = 1 - 0.3 \\ log(5) = 0.7$